Solve 3/4y+x=1

$$\frac { 3 } { 4 } y + x = 1$$

Solve for y

$$y=\frac{4-4x}{3}$$

Steps for Solving Linear Equation

Subtract x from both sides.

$$\frac{3}{4}y=1-x$$

Divide both sides of the equation by \frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{4}y}{\frac{3}{4}}=\frac{1-x}{\frac{3}{4}}$$

Dividing by \frac{3}{4} undoes the multiplication by \frac{3}{4}.

$$y=\frac{1-x}{\frac{3}{4}}$$

Divide 1-x by \frac{3}{4} by multiplying 1-x by the reciprocal of \frac{3}{4}.

$$y=\frac{4-4x}{3}$$

Solve for x

$$x=-\frac{3y}{4}+1$$

Solution Steps

Subtract \frac{3}{4}y from both sides.

$$x=1-\frac{3}{4}y$$