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\frac{27}{4}y+\frac{9}{2}=3
Combine \frac{3}{4}y and 6y to get \frac{27}{4}y.
\frac{27}{4}y=3-\frac{9}{2}
Subtract \frac{9}{2} from both sides.
\frac{27}{4}y=\frac{6}{2}-\frac{9}{2}
Convert 3 to fraction \frac{6}{2}.
\frac{27}{4}y=\frac{6-9}{2}
Since \frac{6}{2} and \frac{9}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{27}{4}y=-\frac{3}{2}
Subtract 9 from 6 to get -3.
y=-\frac{3}{2}\times \frac{4}{27}
Multiply both sides by \frac{4}{27}, the reciprocal of \frac{27}{4}.
y=\frac{-3\times 4}{2\times 27}
Multiply -\frac{3}{2} times \frac{4}{27} by multiplying numerator times numerator and denominator times denominator.
y=\frac{-12}{54}
Do the multiplications in the fraction \frac{-3\times 4}{2\times 27}.
y=-\frac{2}{9}
Reduce the fraction \frac{-12}{54} to lowest terms by extracting and canceling out 6.