Solve 3/4x-4y=1

$$\frac { 3 } { 4 } x - 4 y = 1$$

Solve for x

$$x=\frac{16y+4}{3}$$

Steps for Solving Linear Equation

Add 4y to both sides.

$$\frac{3}{4}x=1+4y$$

The equation is in standard form.

$$\frac{3}{4}x=4y+1$$

Divide both sides of the equation by \frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{4}x}{\frac{3}{4}}=\frac{4y+1}{\frac{3}{4}}$$

Dividing by \frac{3}{4} undoes the multiplication by \frac{3}{4}.

$$x=\frac{4y+1}{\frac{3}{4}}$$

Divide 1+4y by \frac{3}{4} by multiplying 1+4y by the reciprocal of \frac{3}{4}.

$$x=\frac{16y+4}{3}$$

Solve for y

$$y=\frac{3x}{16}-\frac{1}{4}$$

Steps for Solving Linear Equation

Subtract \frac{3}{4}x from both sides.

$$-4y=1-\frac{3}{4}x$$

The equation is in standard form.

$$-4y=-\frac{3x}{4}+1$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{-\frac{3x}{4}+1}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{-\frac{3x}{4}+1}{-4}$$

Divide 1-\frac{3x}{4} by -4.

$$y=\frac{3x}{16}-\frac{1}{4}$$