Solve for x
x=\frac{8\left(y+4\right)}{3}
Solve for y
y=\frac{3x}{8}-4
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\frac{3}{4}x-2y=8
Divide 6 by 3 to get 2.
\frac{3}{4}x=8+2y
Add 2y to both sides.
\frac{3}{4}x=2y+8
The equation is in standard form.
\frac{\frac{3}{4}x}{\frac{3}{4}}=\frac{2y+8}{\frac{3}{4}}
Divide both sides of the equation by \frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{2y+8}{\frac{3}{4}}
Dividing by \frac{3}{4} undoes the multiplication by \frac{3}{4}.
x=\frac{8y+32}{3}
Divide 8+2y by \frac{3}{4} by multiplying 8+2y by the reciprocal of \frac{3}{4}.
\frac{3}{4}x-2y=8
Divide 6 by 3 to get 2.
-2y=8-\frac{3}{4}x
Subtract \frac{3}{4}x from both sides.
-2y=-\frac{3x}{4}+8
The equation is in standard form.
\frac{-2y}{-2}=\frac{-\frac{3x}{4}+8}{-2}
Divide both sides by -2.
y=\frac{-\frac{3x}{4}+8}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{3x}{8}-4
Divide 8-\frac{3x}{4} by -2.
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y = 3x + 4
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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