Solve for x
x = \frac{7}{6} = 1\frac{1}{6} \approx 1.166666667
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\frac{3}{4}x-\frac{1}{8}=\frac{5+1}{8}
Since \frac{5}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.
\frac{3}{4}x-\frac{1}{8}=\frac{6}{8}
Add 5 and 1 to get 6.
\frac{3}{4}x-\frac{1}{8}=\frac{3}{4}
Reduce the fraction \frac{6}{8} to lowest terms by extracting and canceling out 2.
\frac{3}{4}x=\frac{3}{4}+\frac{1}{8}
Add \frac{1}{8} to both sides.
\frac{3}{4}x=\frac{6}{8}+\frac{1}{8}
Least common multiple of 4 and 8 is 8. Convert \frac{3}{4} and \frac{1}{8} to fractions with denominator 8.
\frac{3}{4}x=\frac{6+1}{8}
Since \frac{6}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.
\frac{3}{4}x=\frac{7}{8}
Add 6 and 1 to get 7.
x=\frac{7}{8}\times \frac{4}{3}
Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}.
x=\frac{7\times 4}{8\times 3}
Multiply \frac{7}{8} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.
x=\frac{28}{24}
Do the multiplications in the fraction \frac{7\times 4}{8\times 3}.
x=\frac{7}{6}
Reduce the fraction \frac{28}{24} to lowest terms by extracting and canceling out 4.
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