Solve for x
x = \frac{41}{2} = 20\frac{1}{2} = 20.5
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6x=15\times 8+3
Multiply both sides of the equation by 8, the least common multiple of 4,8.
6x=120+3
Multiply 15 and 8 to get 120.
6x=123
Add 120 and 3 to get 123.
x=\frac{123}{6}
Divide both sides by 6.
x=\frac{41}{2}
Reduce the fraction \frac{123}{6} to lowest terms by extracting and canceling out 3.
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