Solve for x
x=0
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\frac{41}{28}x=2x+\frac{1}{2}x
Combine \frac{3}{4}x and \frac{5}{7}x to get \frac{41}{28}x.
\frac{41}{28}x=\frac{5}{2}x
Combine 2x and \frac{1}{2}x to get \frac{5}{2}x.
\frac{41}{28}x-\frac{5}{2}x=0
Subtract \frac{5}{2}x from both sides.
-\frac{29}{28}x=0
Combine \frac{41}{28}x and -\frac{5}{2}x to get -\frac{29}{28}x.
x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since -\frac{29}{28} is not equal to 0, x must be equal to 0.
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