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\frac{3}{4}x=\frac{3}{8}-\frac{3}{2}
Subtract \frac{3}{2} from both sides.
\frac{3}{4}x=\frac{3}{8}-\frac{12}{8}
Least common multiple of 8 and 2 is 8. Convert \frac{3}{8} and \frac{3}{2} to fractions with denominator 8.
\frac{3}{4}x=\frac{3-12}{8}
Since \frac{3}{8} and \frac{12}{8} have the same denominator, subtract them by subtracting their numerators.
\frac{3}{4}x=-\frac{9}{8}
Subtract 12 from 3 to get -9.
x=-\frac{9}{8}\times \frac{4}{3}
Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}.
x=\frac{-9\times 4}{8\times 3}
Multiply -\frac{9}{8} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-36}{24}
Do the multiplications in the fraction \frac{-9\times 4}{8\times 3}.
x=-\frac{3}{2}
Reduce the fraction \frac{-36}{24} to lowest terms by extracting and canceling out 12.