Solve 3/4b=3b+3

$$\frac { 3 } { 4 } b = 3 b + 3$$

Solve for b

$$b = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$$

Steps for Solving Linear Equation

Subtract 3b from both sides.

$$\frac{3}{4}b-3b=3$$

Combine \frac{3}{4}b and -3b to get -\frac{9}{4}b.

$$-\frac{9}{4}b=3$$

Multiply both sides by -\frac{4}{9}, the reciprocal of -\frac{9}{4}.

$$b=3\left(-\frac{4}{9}\right)$$

Express 3\left(-\frac{4}{9}\right) as a single fraction.

$$b=\frac{3\left(-4\right)}{9}$$

Multiply 3 and -4 to get -12.

$$b=\frac{-12}{9}$$

Reduce the fraction \frac{-12}{9} to lowest terms by extracting and canceling out 3.

$$b=-\frac{4}{3}$$