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\frac{3}{4}-\frac{3}{8}x+\frac{1}{2}x=\frac{1}{2}
Add \frac{1}{2}x to both sides.
\frac{3}{4}+\frac{1}{8}x=\frac{1}{2}
Combine -\frac{3}{8}x and \frac{1}{2}x to get \frac{1}{8}x.
\frac{1}{8}x=\frac{1}{2}-\frac{3}{4}
Subtract \frac{3}{4} from both sides.
\frac{1}{8}x=\frac{2}{4}-\frac{3}{4}
Least common multiple of 2 and 4 is 4. Convert \frac{1}{2} and \frac{3}{4} to fractions with denominator 4.
\frac{1}{8}x=\frac{2-3}{4}
Since \frac{2}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{8}x=-\frac{1}{4}
Subtract 3 from 2 to get -1.
x=-\frac{1}{4}\times 8
Multiply both sides by 8, the reciprocal of \frac{1}{8}.
x=\frac{-8}{4}
Express -\frac{1}{4}\times 8 as a single fraction.
x=-2
Divide -8 by 4 to get -2.