Solve 3/4-2/3x=11/12

$$\frac { 3 } { 4 } - \frac { 2 } { 3 } x = \frac { 11 } { 12 }$$

Solve for x

$$x=-\frac{1}{4}=-0.25$$

Steps for Solving Linear Equation

Subtract \frac{3}{4} from both sides.

$$-\frac{2}{3}x=\frac{11}{12}-\frac{3}{4}$$

Least common multiple of 12 and 4 is 12. Convert \frac{11}{12} and \frac{3}{4} to fractions with denominator 12.

$$-\frac{2}{3}x=\frac{11}{12}-\frac{9}{12}$$

Since \frac{11}{12} and \frac{9}{12} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{2}{3}x=\frac{11-9}{12}$$

Subtract 9 from 11 to get 2.

$$-\frac{2}{3}x=\frac{2}{12}$$

Reduce the fraction \frac{2}{12} to lowest terms by extracting and canceling out 2.

$$-\frac{2}{3}x=\frac{1}{6}$$

Multiply both sides by -\frac{3}{2}, the reciprocal of -\frac{2}{3}.

$$x=\frac{1}{6}\left(-\frac{3}{2}\right)$$

Multiply \frac{1}{6} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{1\left(-3\right)}{6\times 2}$$

Do the multiplications in the fraction \frac{1\left(-3\right)}{6\times 2}.

$$x=\frac{-3}{12}$$

Reduce the fraction \frac{-3}{12} to lowest terms by extracting and canceling out 3.

$$x=-\frac{1}{4}$$