Solve for z
z=-24
Quiz
Linear Equation
5 problems similar to:
\frac { 3 } { 4 } ( z + 8 ) = \frac { 1 } { 3 } ( z - 12 )
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\frac{3}{4}z+\frac{3}{4}\times 8=\frac{1}{3}\left(z-12\right)
Use the distributive property to multiply \frac{3}{4} by z+8.
\frac{3}{4}z+\frac{3\times 8}{4}=\frac{1}{3}\left(z-12\right)
Express \frac{3}{4}\times 8 as a single fraction.
\frac{3}{4}z+\frac{24}{4}=\frac{1}{3}\left(z-12\right)
Multiply 3 and 8 to get 24.
\frac{3}{4}z+6=\frac{1}{3}\left(z-12\right)
Divide 24 by 4 to get 6.
\frac{3}{4}z+6=\frac{1}{3}z+\frac{1}{3}\left(-12\right)
Use the distributive property to multiply \frac{1}{3} by z-12.
\frac{3}{4}z+6=\frac{1}{3}z+\frac{-12}{3}
Multiply \frac{1}{3} and -12 to get \frac{-12}{3}.
\frac{3}{4}z+6=\frac{1}{3}z-4
Divide -12 by 3 to get -4.
\frac{3}{4}z+6-\frac{1}{3}z=-4
Subtract \frac{1}{3}z from both sides.
\frac{5}{12}z+6=-4
Combine \frac{3}{4}z and -\frac{1}{3}z to get \frac{5}{12}z.
\frac{5}{12}z=-4-6
Subtract 6 from both sides.
\frac{5}{12}z=-10
Subtract 6 from -4 to get -10.
z=-10\times \frac{12}{5}
Multiply both sides by \frac{12}{5}, the reciprocal of \frac{5}{12}.
z=\frac{-10\times 12}{5}
Express -10\times \frac{12}{5} as a single fraction.
z=\frac{-120}{5}
Multiply -10 and 12 to get -120.
z=-24
Divide -120 by 5 to get -24.
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