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\frac{3}{4}x+\frac{3}{4}\left(-8\right)-4x=2\left(x-3\right)-\frac{1}{2}x
Use the distributive property to multiply \frac{3}{4} by x-8.
\frac{3}{4}x+\frac{3\left(-8\right)}{4}-4x=2\left(x-3\right)-\frac{1}{2}x
Express \frac{3}{4}\left(-8\right) as a single fraction.
\frac{3}{4}x+\frac{-24}{4}-4x=2\left(x-3\right)-\frac{1}{2}x
Multiply 3 and -8 to get -24.
\frac{3}{4}x-6-4x=2\left(x-3\right)-\frac{1}{2}x
Divide -24 by 4 to get -6.
-\frac{13}{4}x-6=2\left(x-3\right)-\frac{1}{2}x
Combine \frac{3}{4}x and -4x to get -\frac{13}{4}x.
-\frac{13}{4}x-6=2x-6-\frac{1}{2}x
Use the distributive property to multiply 2 by x-3.
-\frac{13}{4}x-6=\frac{3}{2}x-6
Combine 2x and -\frac{1}{2}x to get \frac{3}{2}x.
-\frac{13}{4}x-6-\frac{3}{2}x=-6
Subtract \frac{3}{2}x from both sides.
-\frac{19}{4}x-6=-6
Combine -\frac{13}{4}x and -\frac{3}{2}x to get -\frac{19}{4}x.
-\frac{19}{4}x=-6+6
Add 6 to both sides.
-\frac{19}{4}x=0
Add -6 and 6 to get 0.
x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since -\frac{19}{4} is not equal to 0, x must be equal to 0.