Solve for x
x\leq \frac{13}{8}
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8x-9\leq 3\times \frac{4}{3}
Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}. Since \frac{3}{4} is positive, the inequality direction remains the same.
8x-9\leq 4
Cancel out 3 and 3.
8x\leq 4+9
Add 9 to both sides.
8x\leq 13
Add 4 and 9 to get 13.
x\leq \frac{13}{8}
Divide both sides by 8. Since 8 is positive, the inequality direction remains the same.
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Limits
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