Solve 3/4(8r-4)=-6

$$\frac { 3 } { 4 } ( 8 r - 4 ) = - 6$$

Solve for r

$$r=-\frac{1}{2}=-0.5$$

Steps for Solving Linear Equation

Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}.

$$8r-4=-6\times \frac{4}{3}$$

Express -6\times \frac{4}{3} as a single fraction.

$$8r-4=\frac{-6\times 4}{3}$$

Multiply -6 and 4 to get -24.

$$8r-4=\frac{-24}{3}$$

Divide -24 by 3 to get -8.

$$8r-4=-8$$

Add 4 to both sides.

$$8r=-8+4$$

Add -8 and 4 to get -4.

$$8r=-4$$

Divide both sides by 8.

$$r=\frac{-4}{8}$$

Reduce the fraction \frac{-4}{8} to lowest terms by extracting and canceling out 4.

$$r=-\frac{1}{2}$$