Solve 3/4(3-7/2)+1/5

$$\frac { 3 } { 4 } ( 3 - \frac { 7 } { 2 } ) + \frac { 1 } { 5 }$$

Evaluate

$$-\frac{7}{40}=-0.175$$

Solution Steps

Convert 3 to fraction \frac{6}{2}.

$$\frac{3}{4}\left(\frac{6}{2}-\frac{7}{2}\right)+\frac{1}{5}$$

Since \frac{6}{2} and \frac{7}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{4}\times \frac{6-7}{2}+\frac{1}{5}$$

Subtract 7 from 6 to get -1.

$$\frac{3}{4}\left(-\frac{1}{2}\right)+\frac{1}{5}$$

Multiply \frac{3}{4} times -\frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\left(-1\right)}{4\times 2}+\frac{1}{5}$$

Do the multiplications in the fraction \frac{3\left(-1\right)}{4\times 2}.

$$\frac{-3}{8}+\frac{1}{5}$$

Fraction \frac{-3}{8} can be rewritten as -\frac{3}{8} by extracting the negative sign.

$$-\frac{3}{8}+\frac{1}{5}$$

Least common multiple of 8 and 5 is 40. Convert -\frac{3}{8} and \frac{1}{5} to fractions with denominator 40.

$$-\frac{15}{40}+\frac{8}{40}$$

Since -\frac{15}{40} and \frac{8}{40} have the same denominator, add them by adding their numerators.

$$\frac{-15+8}{40}$$

Add -15 and 8 to get -7.

$$-\frac{7}{40}$$

Factor

$$-\frac{7}{40} = -0.175$$