Solve 3/4(-10+2/5)quad{l}{text{per}h}{text{man}}{text{entir}}

$$\frac { 3 } { 4 } ( - 10 + \frac { 2 } { 5 } ) \quad \left. \begin{array} { l } { \text { per } h } \\ { \text { man } } \\ { \text { entir } } \end{array} \right.$$

Evaluate

$$-\frac{36}{5}=-7.2$$

Solution Steps

Convert -10 to fraction -\frac{50}{5}.

$$\frac{3}{4}\left(-\frac{50}{5}+\frac{2}{5}\right)$$

Since -\frac{50}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$\frac{3}{4}\times \frac{-50+2}{5}$$

Add -50 and 2 to get -48.

$$\frac{3}{4}\left(-\frac{48}{5}\right)$$

Multiply \frac{3}{4} times -\frac{48}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\left(-48\right)}{4\times 5}$$

Do the multiplications in the fraction \frac{3\left(-48\right)}{4\times 5}.

$$\frac{-144}{20}$$

Reduce the fraction \frac{-144}{20} to lowest terms by extracting and canceling out 4.

$$-\frac{36}{5}$$

Factor

$$-\frac{36}{5} = -7\frac{1}{5} = -7.2$$