Solve 3/4*21/3+21/32

$$\frac { 3 } { 4 } \times 2 \frac { 1 } { 3 } + \frac { 21 } { 32 }$$

Evaluate

$$\frac{77}{32}=2.40625$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{3}{4}\times \frac{6+1}{3}+\frac{21}{32}$$

Add 6 and 1 to get 7.

$$\frac{3}{4}\times \frac{7}{3}+\frac{21}{32}$$

Multiply \frac{3}{4} times \frac{7}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 7}{4\times 3}+\frac{21}{32}$$

Cancel out 3 in both numerator and denominator.

$$\frac{7}{4}+\frac{21}{32}$$

Least common multiple of 4 and 32 is 32. Convert \frac{7}{4} and \frac{21}{32} to fractions with denominator 32.

$$\frac{56}{32}+\frac{21}{32}$$

Since \frac{56}{32} and \frac{21}{32} have the same denominator, add them by adding their numerators.

$$\frac{56+21}{32}$$

Add 56 and 21 to get 77.

$$\frac{77}{32}$$

Factor

$$\frac{7 \cdot 11}{2 ^ {5}} = 2\frac{13}{32} = 2.40625$$