Solve 3/4text{of}(11/3+3/5)

$$\frac { 3 } { 4 } \text { of } ( 1 \frac { 1 } { 3 } + \frac { 3 } { 5 } )$$

Evaluate

$$\frac{29}{20}=1.45$$

Solution Steps

Multiply 1 and 3 to get 3.

$$\frac{3}{4}\left(\frac{3+1}{3}+\frac{3}{5}\right)$$

Add 3 and 1 to get 4.

$$\frac{3}{4}\left(\frac{4}{3}+\frac{3}{5}\right)$$

Least common multiple of 3 and 5 is 15. Convert \frac{4}{3} and \frac{3}{5} to fractions with denominator 15.

$$\frac{3}{4}\left(\frac{20}{15}+\frac{9}{15}\right)$$

Since \frac{20}{15} and \frac{9}{15} have the same denominator, add them by adding their numerators.

$$\frac{3}{4}\times \frac{20+9}{15}$$

Add 20 and 9 to get 29.

$$\frac{3}{4}\times \frac{29}{15}$$

Multiply \frac{3}{4} times \frac{29}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 29}{4\times 15}$$

Do the multiplications in the fraction \frac{3\times 29}{4\times 15}.

$$\frac{87}{60}$$

Reduce the fraction \frac{87}{60} to lowest terms by extracting and canceling out 3.

$$\frac{29}{20}$$

Factor

$$\frac{29}{2 ^ {2} \cdot 5} = 1\frac{9}{20} = 1.45$$