Solve 3/4*(1/3-1/9)

$$\frac { 3 } { 4 } \cdot ( \frac { 1 } { 3 } - \frac { 1 } { 9 } )$$

Evaluate

$$\frac{1}{6}\approx 0.166666667$$

Solution Steps

Least common multiple of 3 and 9 is 9. Convert \frac{1}{3} and \frac{1}{9} to fractions with denominator 9.

$$\frac{3}{4}\left(\frac{3}{9}-\frac{1}{9}\right)$$

Since \frac{3}{9} and \frac{1}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{4}\times \frac{3-1}{9}$$

Subtract 1 from 3 to get 2.

$$\frac{3}{4}\times \frac{2}{9}$$

Multiply \frac{3}{4} times \frac{2}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 2}{4\times 9}$$

Do the multiplications in the fraction \frac{3\times 2}{4\times 9}.

$$\frac{6}{36}$$

Reduce the fraction \frac{6}{36} to lowest terms by extracting and canceling out 6.

$$\frac{1}{6}$$

Factor

$$\frac{1}{2 \cdot 3} = 0.16666666666666666$$