Solve 3/4+6/7*7/36=

$$\frac { 3 } { 4 } + \frac { 6 } { 7 } \cdot \frac { 7 } { 36 } =$$

Evaluate

$$\frac{11}{12}\approx 0.916666667$$

Solution Steps

Multiply \frac{6}{7} times \frac{7}{36} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{4}+\frac{6\times 7}{7\times 36}$$

Cancel out 7 in both numerator and denominator.

$$\frac{3}{4}+\frac{6}{36}$$

Reduce the fraction \frac{6}{36} to lowest terms by extracting and canceling out 6.

$$\frac{3}{4}+\frac{1}{6}$$

Least common multiple of 4 and 6 is 12. Convert \frac{3}{4} and \frac{1}{6} to fractions with denominator 12.

$$\frac{9}{12}+\frac{2}{12}$$

Since \frac{9}{12} and \frac{2}{12} have the same denominator, add them by adding their numerators.

$$\frac{9+2}{12}$$

Add 9 and 2 to get 11.

$$\frac{11}{12}$$

Factor

$$\frac{11}{2 ^ {2} \cdot 3} = 0.9166666666666666$$