Solve 3/4+3/4x+(3/4+1/3)=frac{25}{12}

$$\frac { 3 } { 4 } + \frac { 3 } { 4 } x + ( \frac { 3 } { 4 } + \frac { 1 } { 3 } ) = \frac { 25 } { 12 }$$

Solve for x

$$x=\frac{1}{3}\approx 0.333333333$$

Steps for Solving Linear Equation

Since \frac{3}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{3+3}{4}+\frac{3}{4}x+\frac{1}{3}=\frac{25}{12}$$

Add 3 and 3 to get 6.

$$\frac{6}{4}+\frac{3}{4}x+\frac{1}{3}=\frac{25}{12}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}+\frac{3}{4}x+\frac{1}{3}=\frac{25}{12}$$

Least common multiple of 2 and 3 is 6. Convert \frac{3}{2} and \frac{1}{3} to fractions with denominator 6.

$$\frac{9}{6}+\frac{3}{4}x+\frac{2}{6}=\frac{25}{12}$$

Since \frac{9}{6} and \frac{2}{6} have the same denominator, add them by adding their numerators.

$$\frac{9+2}{6}+\frac{3}{4}x=\frac{25}{12}$$

Add 9 and 2 to get 11.

$$\frac{11}{6}+\frac{3}{4}x=\frac{25}{12}$$

Subtract \frac{11}{6} from both sides.

$$\frac{3}{4}x=\frac{25}{12}-\frac{11}{6}$$

Least common multiple of 12 and 6 is 12. Convert \frac{25}{12} and \frac{11}{6} to fractions with denominator 12.

$$\frac{3}{4}x=\frac{25}{12}-\frac{22}{12}$$

Since \frac{25}{12} and \frac{22}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{4}x=\frac{25-22}{12}$$

Subtract 22 from 25 to get 3.

$$\frac{3}{4}x=\frac{3}{12}$$

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$\frac{3}{4}x=\frac{1}{4}$$

Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}.

$$x=\frac{1}{4}\times \frac{4}{3}$$

Multiply \frac{1}{4} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{1\times 4}{4\times 3}$$

Cancel out 4 in both numerator and denominator.

$$x=\frac{1}{3}$$