Solve for x
x=\frac{3}{8}=0.375
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Linear Equation
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\frac { 3 } { 4 } + \frac { 2 } { 5 } x = \frac { 9 } { 10 }
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\frac{2}{5}x=\frac{9}{10}-\frac{3}{4}
Subtract \frac{3}{4} from both sides.
\frac{2}{5}x=\frac{18}{20}-\frac{15}{20}
Least common multiple of 10 and 4 is 20. Convert \frac{9}{10} and \frac{3}{4} to fractions with denominator 20.
\frac{2}{5}x=\frac{18-15}{20}
Since \frac{18}{20} and \frac{15}{20} have the same denominator, subtract them by subtracting their numerators.
\frac{2}{5}x=\frac{3}{20}
Subtract 15 from 18 to get 3.
x=\frac{3}{20}\times \frac{5}{2}
Multiply both sides by \frac{5}{2}, the reciprocal of \frac{2}{5}.
x=\frac{3\times 5}{20\times 2}
Multiply \frac{3}{20} times \frac{5}{2} by multiplying numerator times numerator and denominator times denominator.
x=\frac{15}{40}
Do the multiplications in the fraction \frac{3\times 5}{20\times 2}.
x=\frac{3}{8}
Reduce the fraction \frac{15}{40} to lowest terms by extracting and canceling out 5.
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{ x } ^ { 2 } - 4 x - 5 = 0
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y = 3x + 4
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}