Solve 3/4+2/3-frac{4{3}}=-13

$$\frac { 3 } { 4 } + \frac { 2 } { 3 - \frac { 4 } { 3 } } = - 13$$

Verify

Solution Steps

Convert 3 to fraction \frac{9}{3}.

$$\frac{3}{4}+\frac{2}{\frac{9}{3}-\frac{4}{3}}=-13$$

Since \frac{9}{3} and \frac{4}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{4}+\frac{2}{\frac{9-4}{3}}=-13$$

Subtract 4 from 9 to get 5.

$$\frac{3}{4}+\frac{2}{\frac{5}{3}}=-13$$

Divide 2 by \frac{5}{3} by multiplying 2 by the reciprocal of \frac{5}{3}.

$$\frac{3}{4}+2\times \frac{3}{5}=-13$$

Express 2\times \frac{3}{5} as a single fraction.

$$\frac{3}{4}+\frac{2\times 3}{5}=-13$$

Multiply 2 and 3 to get 6.

$$\frac{3}{4}+\frac{6}{5}=-13$$

Least common multiple of 4 and 5 is 20. Convert \frac{3}{4} and \frac{6}{5} to fractions with denominator 20.

$$\frac{15}{20}+\frac{24}{20}=-13$$

Since \frac{15}{20} and \frac{24}{20} have the same denominator, add them by adding their numerators.

$$\frac{15+24}{20}=-13$$

Add 15 and 24 to get 39.

$$\frac{39}{20}=-13$$

Convert -13 to fraction -\frac{260}{20}.

$$\frac{39}{20}=-\frac{260}{20}$$

Compare \frac{39}{20} and -\frac{260}{20}.

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