Solve 3/4+1/5leqx/3

$$\frac { 3 } { 4 } + \frac { 1 } { 5 } \leq \frac { x } { 3 }$$

Solve for x

$$x\geq \frac{57}{20}$$

Solution Steps

Multiply both sides of the equation by 60, the least common multiple of 4,5,3. Since 60 is positive, the inequality direction remains the same.

$$45+12\leq 20x$$

Add 45 and 12 to get 57.

$$57\leq 20x$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$20x\geq 57$$

Divide both sides by 20. Since 20 is positive, the inequality direction remains the same.

$$x\geq \frac{57}{20}$$