Solve 3/32+11/16+1/8

$$\frac { 3 } { 32 } + 1 \frac { 1 } { 16 } + \frac { 1 } { 8 }$$

Evaluate

$$\frac{41}{32}=1.28125$$

Solution Steps

Multiply 1 and 16 to get 16.

$$\frac{3}{32}+\frac{16+1}{16}+\frac{1}{8}$$

Add 16 and 1 to get 17.

$$\frac{3}{32}+\frac{17}{16}+\frac{1}{8}$$

Least common multiple of 32 and 16 is 32. Convert \frac{3}{32} and \frac{17}{16} to fractions with denominator 32.

$$\frac{3}{32}+\frac{34}{32}+\frac{1}{8}$$

Since \frac{3}{32} and \frac{34}{32} have the same denominator, add them by adding their numerators.

$$\frac{3+34}{32}+\frac{1}{8}$$

Add 3 and 34 to get 37.

$$\frac{37}{32}+\frac{1}{8}$$

Least common multiple of 32 and 8 is 32. Convert \frac{37}{32} and \frac{1}{8} to fractions with denominator 32.

$$\frac{37}{32}+\frac{4}{32}$$

Since \frac{37}{32} and \frac{4}{32} have the same denominator, add them by adding their numerators.

$$\frac{37+4}{32}$$

Add 37 and 4 to get 41.

$$\frac{41}{32}$$

Factor

$$\frac{41}{2 ^ {5}} = 1\frac{9}{32} = 1.28125$$