Solve 3/3:(211.9+212.95+215.20)/2=

$$\frac { 3 } { 3 } : \frac { ( 211.9 + 212.95 + 215.20 ) } { 2 } =$$

Evaluate

$$\frac{40}{12801}\approx 0.003124756$$

Solution Steps

Divide 3 by 3 to get 1.

$$\frac{1}{\frac{211.9+212.95+215.2}{2}}$$

Divide 1 by \frac{211.9+212.95+215.2}{2} by multiplying 1 by the reciprocal of \frac{211.9+212.95+215.2}{2}.

$$\frac{2}{211.9+212.95+215.2}$$

Add 211.9 and 212.95 to get 424.85.

$$\frac{2}{424.85+215.2}$$

Add 424.85 and 215.2 to get 640.05.

$$\frac{2}{640.05}$$

Expand \frac{2}{640.05} by multiplying both numerator and the denominator by 100.

$$\frac{200}{64005}$$

Reduce the fraction \frac{200}{64005} to lowest terms by extracting and canceling out 5.

$$\frac{40}{12801}$$

Factor

$$\frac{5 \cdot 2 ^ {3}}{3 \cdot 17 \cdot 251} = 0.0031247558784469965$$