Solve 3/3+2+2*4/2+3+4

$$\frac { 3 } { 3 + 2 + 2 } \times \frac { 4 } { 2 + 3 + 4 }$$

Evaluate

$$\frac{4}{21}\approx 0.19047619$$

Solution Steps

Add 3 and 2 to get 5.

$$\frac{3}{5+2}\times \frac{4}{2+3+4}$$

Add 5 and 2 to get 7.

$$\frac{3}{7}\times \frac{4}{2+3+4}$$

Add 2 and 3 to get 5.

$$\frac{3}{7}\times \frac{4}{5+4}$$

Add 5 and 4 to get 9.

$$\frac{3}{7}\times \frac{4}{9}$$

Multiply \frac{3}{7} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 4}{7\times 9}$$

Do the multiplications in the fraction \frac{3\times 4}{7\times 9}.

$$\frac{12}{63}$$

Reduce the fraction \frac{12}{63} to lowest terms by extracting and canceling out 3.

$$\frac{4}{21}$$

Factor

$$\frac{2 ^ {2}}{3 \cdot 7} = 0.19047619047619047$$