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\frac{3}{3+1}+\frac{5}{11}-\left(\frac{3}{5}-\frac{12}{20}\right)\times \frac{123}{456}
Divide 2 by 2 to get 1.
\frac{3}{4}+\frac{5}{11}-\left(\frac{3}{5}-\frac{12}{20}\right)\times \frac{123}{456}
Add 3 and 1 to get 4.
\frac{33}{44}+\frac{20}{44}-\left(\frac{3}{5}-\frac{12}{20}\right)\times \frac{123}{456}
Least common multiple of 4 and 11 is 44. Convert \frac{3}{4} and \frac{5}{11} to fractions with denominator 44.
\frac{33+20}{44}-\left(\frac{3}{5}-\frac{12}{20}\right)\times \frac{123}{456}
Since \frac{33}{44} and \frac{20}{44} have the same denominator, add them by adding their numerators.
\frac{53}{44}-\left(\frac{3}{5}-\frac{12}{20}\right)\times \frac{123}{456}
Add 33 and 20 to get 53.
\frac{53}{44}-\left(\frac{3}{5}-\frac{3}{5}\right)\times \frac{123}{456}
Reduce the fraction \frac{12}{20} to lowest terms by extracting and canceling out 4.
\frac{53}{44}-0\times \frac{123}{456}
Subtract \frac{3}{5} from \frac{3}{5} to get 0.
\frac{53}{44}-0\times \frac{41}{152}
Reduce the fraction \frac{123}{456} to lowest terms by extracting and canceling out 3.
\frac{53}{44}-0
Multiply 0 and \frac{41}{152} to get 0.
\frac{53}{44}
Subtract 0 from \frac{53}{44} to get \frac{53}{44}.