Solve for x
x=21
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\left(x+5\right)\times 3=\left(2x-3\right)\times 2
Variable x cannot be equal to any of the values -5,\frac{3}{2} since division by zero is not defined. Multiply both sides of the equation by \left(2x-3\right)\left(x+5\right), the least common multiple of 2x-3,x+5.
3x+15=\left(2x-3\right)\times 2
Use the distributive property to multiply x+5 by 3.
3x+15=4x-6
Use the distributive property to multiply 2x-3 by 2.
3x+15-4x=-6
Subtract 4x from both sides.
-x+15=-6
Combine 3x and -4x to get -x.
-x=-6-15
Subtract 15 from both sides.
-x=-21
Subtract 15 from -6 to get -21.
x=21
Multiply both sides by -1.
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