Solve 3/2x+3/-x

$$\frac { 3 } { 2 x } + \frac { 3 } { - x }$$

Evaluate

$$-\frac{3}{2x}$$

Short Solution Steps

Factor -x.

$$\frac{3}{2x}+\frac{3}{-x}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 2x and -x is 2x. Multiply \frac{3}{-x} times \frac{-2}{-2}.

$$\frac{3}{2x}+\frac{3\left(-2\right)}{2x}$$

Since \frac{3}{2x} and \frac{3\left(-2\right)}{2x} have the same denominator, add them by adding their numerators.

$$\frac{3+3\left(-2\right)}{2x}$$

Do the multiplications in 3+3\left(-2\right).

$$\frac{3-6}{2x}$$

Do the calculations in 3-6.

$$\frac{-3}{2x}$$

Differentiate w.r.t. x

$$\frac{3}{2x^{2}}$$