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\frac{3\left(2+\sqrt{2}\right)}{\left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right)}
Rationalize the denominator of \frac{3}{2-\sqrt{2}} by multiplying numerator and denominator by 2+\sqrt{2}.
\frac{3\left(2+\sqrt{2}\right)}{2^{2}-\left(\sqrt{2}\right)^{2}}
Consider \left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{3\left(2+\sqrt{2}\right)}{4-2}
Square 2. Square \sqrt{2}.
\frac{3\left(2+\sqrt{2}\right)}{2}
Subtract 2 from 4 to get 2.
\frac{6+3\sqrt{2}}{2}
Use the distributive property to multiply 3 by 2+\sqrt{2}.