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\frac{3\left(4x^{5}y^{3}-9x^{3}y^{5}\right)}{8}
Factor out \frac{3}{8}.
x^{3}y^{3}\left(4x^{2}-9y^{2}\right)
Consider 4x^{5}y^{3}-9x^{3}y^{5}. Factor out x^{3}y^{3}.
\left(2x-3y\right)\left(2x+3y\right)
Consider 4x^{2}-9y^{2}. Rewrite 4x^{2}-9y^{2} as \left(2x\right)^{2}-\left(3y\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{3x^{3}y^{3}\left(2x-3y\right)\left(2x+3y\right)}{8}
Rewrite the complete factored expression.