Solve 3/2x^2*(-6xy)*1/3x

$$\frac { 3 } { 2 } x ^ { 2 } \times ( - 6 x y ) \times \frac { 1 } { 3 } x$$

Evaluate

$$-3yx^{4}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{3}{2}x^{3}\left(-6\right)y\times \frac{1}{3}x$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$\frac{3}{2}x^{4}\left(-6\right)y\times \frac{1}{3}$$

Multiply \frac{3}{2} and -6 to get -9.

$$-9x^{4}y\times \frac{1}{3}$$

Multiply -9 and \frac{1}{3} to get -3.

$$-3x^{4}y$$

Differentiate w.r.t. x

$$-12yx^{3}$$