Solve for x
x=-\frac{8y}{3}+13
Solve for y
y=\frac{39-3x}{8}
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3x+8y=19\times 2+1
Multiply both sides of the equation by 2.
3x+8y=38+1
Multiply 19 and 2 to get 38.
3x+8y=39
Add 38 and 1 to get 39.
3x=39-8y
Subtract 8y from both sides.
\frac{3x}{3}=\frac{39-8y}{3}
Divide both sides by 3.
x=\frac{39-8y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{8y}{3}+13
Divide 39-8y by 3.
3x+8y=19\times 2+1
Multiply both sides of the equation by 2.
3x+8y=38+1
Multiply 19 and 2 to get 38.
3x+8y=39
Add 38 and 1 to get 39.
8y=39-3x
Subtract 3x from both sides.
\frac{8y}{8}=\frac{39-3x}{8}
Divide both sides by 8.
y=\frac{39-3x}{8}
Dividing by 8 undoes the multiplication by 8.
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