Solve 3/2x+3+3/4=1/4x

$$\frac { 3 } { 2 } x + 3 + \frac { 3 } { 4 } = \frac { 1 } { 4 } x$$

Solve for x

$$x=-3$$

Steps for Solving Linear Equation

Convert 3 to fraction \frac{12}{4}.

$$\frac{3}{2}x+\frac{12}{4}+\frac{3}{4}=\frac{1}{4}x$$

Since \frac{12}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{3}{2}x+\frac{12+3}{4}=\frac{1}{4}x$$

Add 12 and 3 to get 15.

$$\frac{3}{2}x+\frac{15}{4}=\frac{1}{4}x$$

Subtract \frac{1}{4}x from both sides.

$$\frac{3}{2}x+\frac{15}{4}-\frac{1}{4}x=0$$

Combine \frac{3}{2}x and -\frac{1}{4}x to get \frac{5}{4}x.

$$\frac{5}{4}x+\frac{15}{4}=0$$

Subtract \frac{15}{4} from both sides. Anything subtracted from zero gives its negation.

$$\frac{5}{4}x=-\frac{15}{4}$$

Multiply both sides by \frac{4}{5}, the reciprocal of \frac{5}{4}.

$$x=-\frac{15}{4}\times \frac{4}{5}$$

Multiply -\frac{15}{4} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-15\times 4}{4\times 5}$$

Cancel out 4 in both numerator and denominator.

$$x=\frac{-15}{5}$$

Divide -15 by 5 to get -3.

$$x=-3$$