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\frac{3}{2}x+\frac{1}{2}-\frac{2}{3}x=-\frac{1}{2}
Subtract \frac{2}{3}x from both sides.
\frac{5}{6}x+\frac{1}{2}=-\frac{1}{2}
Combine \frac{3}{2}x and -\frac{2}{3}x to get \frac{5}{6}x.
\frac{5}{6}x=-\frac{1}{2}-\frac{1}{2}
Subtract \frac{1}{2} from both sides.
\frac{5}{6}x=\frac{-1-1}{2}
Since -\frac{1}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{5}{6}x=\frac{-2}{2}
Subtract 1 from -1 to get -2.
\frac{5}{6}x=-1
Divide -2 by 2 to get -1.
x=-\frac{6}{5}
Multiply both sides by \frac{6}{5}, the reciprocal of \frac{5}{6}.