Solve 3/2-5/1+3/4-11/2+3

$$\frac { 3 } { 2 } - \frac { 5 } { 1 } + \frac { 3 } { 4 } - 1 \frac { 1 } { 2 } + 3$$

Evaluate

$$-\frac{5}{4}=-1.25$$

Solution Steps

Anything divided by one gives itself.

$$\frac{3}{2}-5+\frac{3}{4}-\frac{1\times 2+1}{2}+3$$

Convert 5 to fraction \frac{10}{2}.

$$\frac{3}{2}-\frac{10}{2}+\frac{3}{4}-\frac{1\times 2+1}{2}+3$$

Since \frac{3}{2} and \frac{10}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-10}{2}+\frac{3}{4}-\frac{1\times 2+1}{2}+3$$

Subtract 10 from 3 to get -7.

$$-\frac{7}{2}+\frac{3}{4}-\frac{1\times 2+1}{2}+3$$

Least common multiple of 2 and 4 is 4. Convert -\frac{7}{2} and \frac{3}{4} to fractions with denominator 4.

$$-\frac{14}{4}+\frac{3}{4}-\frac{1\times 2+1}{2}+3$$

Since -\frac{14}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{-14+3}{4}-\frac{1\times 2+1}{2}+3$$

Add -14 and 3 to get -11.

$$-\frac{11}{4}-\frac{1\times 2+1}{2}+3$$

Multiply 1 and 2 to get 2.

$$-\frac{11}{4}-\frac{2+1}{2}+3$$

Add 2 and 1 to get 3.

$$-\frac{11}{4}-\frac{3}{2}+3$$

Least common multiple of 4 and 2 is 4. Convert -\frac{11}{4} and \frac{3}{2} to fractions with denominator 4.

$$-\frac{11}{4}-\frac{6}{4}+3$$

Since -\frac{11}{4} and \frac{6}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-11-6}{4}+3$$

Subtract 6 from -11 to get -17.

$$-\frac{17}{4}+3$$

Convert 3 to fraction \frac{12}{4}.

$$-\frac{17}{4}+\frac{12}{4}$$

Since -\frac{17}{4} and \frac{12}{4} have the same denominator, add them by adding their numerators.

$$\frac{-17+12}{4}$$

Add -17 and 12 to get -5.

$$-\frac{5}{4}$$

Factor

$$-\frac{5}{4} = -1\frac{1}{4} = -1.25$$