Solve 3/2(3-u)^2

$$\frac { 3 } { 2 } ( 3 - u ) ^ { 2 }$$

Evaluate

$$\frac{3\left(3-u\right)^{2}}{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3-u\right)^{2}.

$$\frac{3}{2}\left(9-6u+u^{2}\right)$$

Use the distributive property to multiply \frac{3}{2} by 9-6u+u^{2}.

$$\frac{27}{2}-9u+\frac{3}{2}u^{2}$$

Expand

$$\frac{3u^{2}}{2}-9u+\frac{27}{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3-u\right)^{2}.

$$\frac{3}{2}\left(9-6u+u^{2}\right)$$

Use the distributive property to multiply \frac{3}{2} by 9-6u+u^{2}.

$$\frac{27}{2}-9u+\frac{3}{2}u^{2}$$