Solve 3/2*((1/2)^4-1)=

$$\frac { 3 } { 2 } \cdot ( ( \frac { 1 } { 2 } ) ^ { 4 } - 1 ) =$$

Evaluate

$$-\frac{45}{32}=-1.40625$$

Solution Steps

Calculate \frac{1}{2} to the power of 4 and get \frac{1}{16}.

$$\frac{3}{2}\left(\frac{1}{16}-1\right)$$

Convert 1 to fraction \frac{16}{16}.

$$\frac{3}{2}\left(\frac{1}{16}-\frac{16}{16}\right)$$

Since \frac{1}{16} and \frac{16}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{2}\times \frac{1-16}{16}$$

Subtract 16 from 1 to get -15.

$$\frac{3}{2}\left(-\frac{15}{16}\right)$$

Multiply \frac{3}{2} times -\frac{15}{16} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\left(-15\right)}{2\times 16}$$

Do the multiplications in the fraction \frac{3\left(-15\right)}{2\times 16}.

$$\frac{-45}{32}$$

Fraction \frac{-45}{32} can be rewritten as -\frac{45}{32} by extracting the negative sign.

$$-\frac{45}{32}$$

Factor

$$-\frac{45}{32} = -1\frac{13}{32} = -1.40625$$