Solve 3/2*4/2-2/3+(1/2)^3=

$$\frac { 3 } { 2 } \cdot \frac { 4 } { 2 } - \frac { 2 } { 3 } + ( \frac { 1 } { 2 } ) ^ { 3 } =$$

Evaluate

$$\frac{59}{24}\approx 2.458333333$$

Solution Steps

Divide 4 by 2 to get 2.

$$\frac{3}{2}\times 2-\frac{2}{3}+\left(\frac{1}{2}\right)^{3}$$

Cancel out 2 and 2.

$$3-\frac{2}{3}+\left(\frac{1}{2}\right)^{3}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{9}{3}-\frac{2}{3}+\left(\frac{1}{2}\right)^{3}$$

Since \frac{9}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-2}{3}+\left(\frac{1}{2}\right)^{3}$$

Subtract 2 from 9 to get 7.

$$\frac{7}{3}+\left(\frac{1}{2}\right)^{3}$$

Calculate \frac{1}{2} to the power of 3 and get \frac{1}{8}.

$$\frac{7}{3}+\frac{1}{8}$$

Least common multiple of 3 and 8 is 24. Convert \frac{7}{3} and \frac{1}{8} to fractions with denominator 24.

$$\frac{56}{24}+\frac{3}{24}$$

Since \frac{56}{24} and \frac{3}{24} have the same denominator, add them by adding their numerators.

$$\frac{56+3}{24}$$

Add 56 and 3 to get 59.

$$\frac{59}{24}$$

Factor

$$\frac{59}{2 ^ {3} \cdot 3} = 2\frac{11}{24} = 2.4583333333333335$$