Solve 3/2=4/3*2+b

$$\frac { 3 } { 2 } = \frac { 4 } { 3 } \cdot 2 + b$$

Solve for b

$$b = -\frac{7}{6} = -1\frac{1}{6} \approx -1.166666667$$

Steps for Solving Linear Equation

Express \frac{4}{3}\times 2 as a single fraction.

$$\frac{3}{2}=\frac{4\times 2}{3}+b$$

Multiply 4 and 2 to get 8.

$$\frac{3}{2}=\frac{8}{3}+b$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{8}{3}+b=\frac{3}{2}$$

Subtract \frac{8}{3} from both sides.

$$b=\frac{3}{2}-\frac{8}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{3}{2} and \frac{8}{3} to fractions with denominator 6.

$$b=\frac{9}{6}-\frac{16}{6}$$

Since \frac{9}{6} and \frac{16}{6} have the same denominator, subtract them by subtracting their numerators.

$$b=\frac{9-16}{6}$$

Subtract 16 from 9 to get -7.

$$b=-\frac{7}{6}$$