Solve 3/12+4/9+1/3=

$$\frac { 3 } { 12 } + \frac { 4 } { 9 } + \frac { 1 } { 3 } =$$

Evaluate

$$\frac{37}{36}\approx 1.027777778$$

Solution Steps

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$\frac{1}{4}+\frac{4}{9}+\frac{1}{3}$$

Least common multiple of 4 and 9 is 36. Convert \frac{1}{4} and \frac{4}{9} to fractions with denominator 36.

$$\frac{9}{36}+\frac{16}{36}+\frac{1}{3}$$

Since \frac{9}{36} and \frac{16}{36} have the same denominator, add them by adding their numerators.

$$\frac{9+16}{36}+\frac{1}{3}$$

Add 9 and 16 to get 25.

$$\frac{25}{36}+\frac{1}{3}$$

Least common multiple of 36 and 3 is 36. Convert \frac{25}{36} and \frac{1}{3} to fractions with denominator 36.

$$\frac{25}{36}+\frac{12}{36}$$

Since \frac{25}{36} and \frac{12}{36} have the same denominator, add them by adding their numerators.

$$\frac{25+12}{36}$$

Add 25 and 12 to get 37.

$$\frac{37}{36}$$

Factor

$$\frac{37}{2 ^ {2} \cdot 3 ^ {2}} = 1\frac{1}{36} = 1.0277777777777777$$