Solve for x
x = \frac{5}{2} = 2\frac{1}{2} = 2.5
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Quiz
Linear Equation
\frac { 3 } { 10 } x + \frac { 1 } { 2 } = \frac { 3 } { 5 } x - \frac { 1 } { 4 }
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\frac{3}{10}x+\frac{1}{2}-\frac{3}{5}x=-\frac{1}{4}
Subtract \frac{3}{5}x from both sides.
-\frac{3}{10}x+\frac{1}{2}=-\frac{1}{4}
Combine \frac{3}{10}x and -\frac{3}{5}x to get -\frac{3}{10}x.
-\frac{3}{10}x=-\frac{1}{4}-\frac{1}{2}
Subtract \frac{1}{2} from both sides.
-\frac{3}{10}x=-\frac{1}{4}-\frac{2}{4}
Least common multiple of 4 and 2 is 4. Convert -\frac{1}{4} and \frac{1}{2} to fractions with denominator 4.
-\frac{3}{10}x=\frac{-1-2}{4}
Since -\frac{1}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.
-\frac{3}{10}x=-\frac{3}{4}
Subtract 2 from -1 to get -3.
x=-\frac{3}{4}\left(-\frac{10}{3}\right)
Multiply both sides by -\frac{10}{3}, the reciprocal of -\frac{3}{10}.
x=\frac{-3\left(-10\right)}{4\times 3}
Multiply -\frac{3}{4} times -\frac{10}{3} by multiplying numerator times numerator and denominator times denominator.
x=\frac{30}{12}
Do the multiplications in the fraction \frac{-3\left(-10\right)}{4\times 3}.
x=\frac{5}{2}
Reduce the fraction \frac{30}{12} to lowest terms by extracting and canceling out 6.
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{ x } ^ { 2 } - 4 x - 5 = 0
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y = 3x + 4
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}