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\frac{3\sqrt{6}}{\left(\sqrt{6}\right)^{2}}\times \frac{\sqrt{2}}{3\sqrt{40}}
Rationalize the denominator of \frac{3}{\sqrt{6}} by multiplying numerator and denominator by \sqrt{6}.
\frac{3\sqrt{6}}{6}\times \frac{\sqrt{2}}{3\sqrt{40}}
The square of \sqrt{6} is 6.
\frac{1}{2}\sqrt{6}\times \frac{\sqrt{2}}{3\sqrt{40}}
Divide 3\sqrt{6} by 6 to get \frac{1}{2}\sqrt{6}.
\frac{1}{2}\sqrt{6}\times \frac{\sqrt{2}}{3\times 2\sqrt{10}}
Factor 40=2^{2}\times 10. Rewrite the square root of the product \sqrt{2^{2}\times 10} as the product of square roots \sqrt{2^{2}}\sqrt{10}. Take the square root of 2^{2}.
\frac{1}{2}\sqrt{6}\times \frac{\sqrt{2}}{6\sqrt{10}}
Multiply 3 and 2 to get 6.
\frac{1}{2}\sqrt{6}\times \frac{\sqrt{2}\sqrt{10}}{6\left(\sqrt{10}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{2}}{6\sqrt{10}} by multiplying numerator and denominator by \sqrt{10}.
\frac{1}{2}\sqrt{6}\times \frac{\sqrt{2}\sqrt{10}}{6\times 10}
The square of \sqrt{10} is 10.
\frac{1}{2}\sqrt{6}\times \frac{\sqrt{2}\sqrt{2}\sqrt{5}}{6\times 10}
Factor 10=2\times 5. Rewrite the square root of the product \sqrt{2\times 5} as the product of square roots \sqrt{2}\sqrt{5}.
\frac{1}{2}\sqrt{6}\times \frac{2\sqrt{5}}{6\times 10}
Multiply \sqrt{2} and \sqrt{2} to get 2.
\frac{1}{2}\sqrt{6}\times \frac{2\sqrt{5}}{60}
Multiply 6 and 10 to get 60.
\frac{1}{2}\sqrt{6}\times \frac{1}{30}\sqrt{5}
Divide 2\sqrt{5} by 60 to get \frac{1}{30}\sqrt{5}.
\frac{1\times 1}{2\times 30}\sqrt{6}\sqrt{5}
Multiply \frac{1}{2} times \frac{1}{30} by multiplying numerator times numerator and denominator times denominator.
\frac{1}{60}\sqrt{6}\sqrt{5}
Do the multiplications in the fraction \frac{1\times 1}{2\times 30}.
\frac{1}{60}\sqrt{30}
To multiply \sqrt{6} and \sqrt{5}, multiply the numbers under the square root.