Solve 3*y^2/40:13y/24a^2b

$$\frac { 3 \times y ^ { 2 } } { 40 } : \frac { 13 y } { 24 a ^ { 2 } b }$$

Evaluate

$$\frac{9bya^{2}}{65}$$

Solution Steps

Divide \frac{3y^{2}}{40} by \frac{13y}{24a^{2}b} by multiplying \frac{3y^{2}}{40} by the reciprocal of \frac{13y}{24a^{2}b}.

$$\frac{3y^{2}\times 24a^{2}b}{40\times 13y}$$

Cancel out 8y in both numerator and denominator.

$$\frac{3\times 3bya^{2}}{5\times 13}$$

Multiply 3 and 3 to get 9.

$$\frac{9bya^{2}}{5\times 13}$$

Multiply 5 and 13 to get 65.

$$\frac{9bya^{2}}{65}$$

Differentiate w.r.t. y

$$\frac{9ba^{2}}{65}$$