Solve 3*10^-12/10^3+(4*10^-5)

$$\frac { 3 \times 10 ^ { - 12 } } { 10 ^ { 3 } + ( 4 \times 10 ^ { - 5 } ) }$$

Evaluate

$$\frac{3}{1000000040000000}\approx 2.99999988 \cdot 10^{-15}$$

Solution Steps

Calculate 10 to the power of -12 and get \frac{1}{1000000000000}.

$$\frac{3\times \frac{1}{1000000000000}}{10^{3}+4\times 10^{-5}}$$

Multiply 3 and \frac{1}{1000000000000} to get \frac{3}{1000000000000}.

$$\frac{\frac{3}{1000000000000}}{10^{3}+4\times 10^{-5}}$$

Calculate 10 to the power of 3 and get 1000.

$$\frac{\frac{3}{1000000000000}}{1000+4\times 10^{-5}}$$

Calculate 10 to the power of -5 and get \frac{1}{100000}.

$$\frac{\frac{3}{1000000000000}}{1000+4\times \frac{1}{100000}}$$

Multiply 4 and \frac{1}{100000} to get \frac{1}{25000}.

$$\frac{\frac{3}{1000000000000}}{1000+\frac{1}{25000}}$$

Add 1000 and \frac{1}{25000} to get \frac{25000001}{25000}.

$$\frac{\frac{3}{1000000000000}}{\frac{25000001}{25000}}$$

Divide \frac{3}{1000000000000} by \frac{25000001}{25000} by multiplying \frac{3}{1000000000000} by the reciprocal of \frac{25000001}{25000}.

$$\frac{3}{1000000000000}\times \frac{25000}{25000001}$$

Multiply \frac{3}{1000000000000} and \frac{25000}{25000001} to get \frac{3}{1000000040000000}.

$$\frac{3}{1000000040000000}$$

Factor

$$\frac{3}{2 ^ {9} \cdot 5 ^ {7} \cdot 13 ^ {2} \cdot 29 \cdot 5101} = 2.9999998800000047 \times 10^{-15}$$