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\frac{3\times 2-\frac{9}{\sqrt{4}}}{\frac{13}{8}-\frac{3^{2}}{8}}
Calculate the square root of 4 and get 2.
\frac{6-\frac{9}{\sqrt{4}}}{\frac{13}{8}-\frac{3^{2}}{8}}
Multiply 3 and 2 to get 6.
\frac{6-\frac{9}{2}}{\frac{13}{8}-\frac{3^{2}}{8}}
Calculate the square root of 4 and get 2.
\frac{\frac{12}{2}-\frac{9}{2}}{\frac{13}{8}-\frac{3^{2}}{8}}
Convert 6 to fraction \frac{12}{2}.
\frac{\frac{12-9}{2}}{\frac{13}{8}-\frac{3^{2}}{8}}
Since \frac{12}{2} and \frac{9}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{3}{2}}{\frac{13}{8}-\frac{3^{2}}{8}}
Subtract 9 from 12 to get 3.
\frac{\frac{3}{2}}{\frac{13}{8}-\frac{9}{8}}
Calculate 3 to the power of 2 and get 9.
\frac{\frac{3}{2}}{\frac{13-9}{8}}
Since \frac{13}{8} and \frac{9}{8} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{3}{2}}{\frac{4}{8}}
Subtract 9 from 13 to get 4.
\frac{\frac{3}{2}}{\frac{1}{2}}
Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.
\frac{3}{2}\times 2
Divide \frac{3}{2} by \frac{1}{2} by multiplying \frac{3}{2} by the reciprocal of \frac{1}{2}.
3
Cancel out 2 and 2.