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\frac{3\times 2\sqrt{3}}{4\sqrt{7}}
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
\frac{6\sqrt{3}}{4\sqrt{7}}
Multiply 3 and 2 to get 6.
\frac{3\sqrt{3}}{2\sqrt{7}}
Cancel out 2 in both numerator and denominator.
\frac{3\sqrt{3}\sqrt{7}}{2\left(\sqrt{7}\right)^{2}}
Rationalize the denominator of \frac{3\sqrt{3}}{2\sqrt{7}} by multiplying numerator and denominator by \sqrt{7}.
\frac{3\sqrt{3}\sqrt{7}}{2\times 7}
The square of \sqrt{7} is 7.
\frac{3\sqrt{21}}{2\times 7}
To multiply \sqrt{3} and \sqrt{7}, multiply the numbers under the square root.
\frac{3\sqrt{21}}{14}
Multiply 2 and 7 to get 14.