Solve 3^7*(-9)^3/(-3)^2*(-27)^3

$$\frac { 3 ^ { 7 } \cdot ( - 9 ) ^ { 3 } } { ( - 3 ) ^ { 2 } \cdot ( - 27 ) ^ { 3 } }$$

Evaluate

$$9$$

Solution Steps

Calculate 3 to the power of 7 and get 2187.

$$\frac{2187\left(-9\right)^{3}}{\left(-3\right)^{2}\left(-27\right)^{3}}$$

Calculate -9 to the power of 3 and get -729.

$$\frac{2187\left(-729\right)}{\left(-3\right)^{2}\left(-27\right)^{3}}$$

Multiply 2187 and -729 to get -1594323.

$$\frac{-1594323}{\left(-3\right)^{2}\left(-27\right)^{3}}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{-1594323}{9\left(-27\right)^{3}}$$

Calculate -27 to the power of 3 and get -19683.

$$\frac{-1594323}{9\left(-19683\right)}$$

Multiply 9 and -19683 to get -177147.

$$\frac{-1594323}{-177147}$$

Divide -1594323 by -177147 to get 9.

$$9$$

Factor

$$3^{2}$$